Given:
First four terms of a sequence are 18,25,32,39....
To find:
The expression for the nth term of the sequence.
Solution:
It is clear that, 18,25,32,39 are in AP.
Here,
First term: a=18
Common difference: d = 25-18 = 7
The nth term of an AP is
[tex]a_n=a+(n-1)d[/tex]
On substituting the values, we get
[tex]a_n=18+(n-1)7[/tex]
[tex]a_n=18+7n-7[/tex]
[tex]a_n=11+7n[/tex]
Therefore, the required expression for nth term of the sequence is [tex]a_n=11+7n[/tex].