Respuesta :

Given:

First four terms of a sequence are 18,25,32,39....

To find:

The expression for the nth term of the sequence.

Solution:

It is clear that, 18,25,32,39 are in AP.

Here,

First term: a=18

Common difference: d = 25-18 = 7

The nth term of an AP is

[tex]a_n=a+(n-1)d[/tex]

On substituting the values, we get

[tex]a_n=18+(n-1)7[/tex]

[tex]a_n=18+7n-7[/tex]

[tex]a_n=11+7n[/tex]

Therefore, the required expression for nth term of the sequence is [tex]a_n=11+7n[/tex].                              

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