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From left to right for the tables :
[tex]1) \: \: \: \: y = 4x + 2[/tex]
And
[tex]2) \: \: \: \: y = 3x - 12[/tex]
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To find the solution we need to take equal above equations .
[tex]4x + 2 = 3x - 12[/tex]
Subtract sides 3x
[tex] - 3x + 4x + 2 = - 3x + 3x - 12 \\ [/tex]
[tex]x + 2 = - 12[/tex]
Subtract sides 2
[tex]x + 2 - 2 = - 12 - 2[/tex]
[tex]x = - 14[/tex]
Thus the x-coordinate of the solution must be -14 which is just in the last option.
Thus the correct answer is the last one.
Done...
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