Respuesta :
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[tex] log(550) = log(2 \times 5 \times 5 \times 11) = \\ [/tex]
[tex] log(2) + log( {5}^{2} ) + log(11) = [/tex]
[tex]1 - log(5) + 2 log(5 ) + log(11) = \\ [/tex]
[tex]1 + log(5) + log(11) = [/tex]
[tex]1 + a + b[/tex]
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Answer:
log(a x b) = Log(550)
Step-by-step explanation:
Depends what question is asking
Log rule (So long as they have the same base)
Log(m) + Log(n) = Log(m x n)
Log(a) + Log(b) = Log(a x b)
Log(5) + Log(11) = Log(5 x 11)
=Log (550)