simplify rs
r (0,a)
s (b,c)
p (b,-c)
q (0,-a)

Answer:
see explanation
Step-by-step explanation:
Calculate RS using the distance formula
d = [tex]\sqrt{(x_{2 -x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = R(0, a) and (x₂, y₂ ) = S(b, c) , thus
RS = [tex]\sqrt{(b-0)^2+(c-a)^2}[/tex]
= [tex]\sqrt{b^2+(c-a)^2}[/tex]
Following are the calculation to the distance of rs:
Given:
Please find the question.
To find:
distance in rs=?
Solution:
Using the formula of distance:
[tex]\to d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
points:
[tex]\to R=(0,a)\\\\\to S=(b,c)[/tex]
[tex]\to (X_1, y_1) = R(0, a) \\\\ \to (x_2, y_2 ) = S(b, c)[/tex]
Calculate RS distance by using the above formula:
[tex]\to RS=\sqrt{(b-0)^2+(c-a)^2}\\\\\to RS=\sqrt{(b)^2+(c-a)^2}\\\\\to RS=\sqrt{(b)^2+(c-a)^2}\\\\[/tex]
Therefore, the final answer is "[tex]\bold{\sqrt{b^2+(c-a)^2}}[/tex]"
Learn more about the distance:
brainly.com/question/12662141