Respuesta :

Answer:

6) H = m[tex]H_{f}[/tex] + mcT

m is 20

Hf is 336

c is 4.2

T is 25

so

    H = 20x336 + 20x4.2x25

 ANSWER IS,

                      H = 8820 J

5) m=5kg=5000gm

   ddifference in temp = 25 C

   Energy or Q = 7000J

To find heat capacity of the piece of metal,

                         [tex]heat capacity= \frac{Energy}{Difference of Temperature}[/tex]

                            [tex]heat capacity = \frac{7000}{25}[/tex]

                         heat capacity = 280 J

   To find specific heat capacity,

                          Q = mcT

          so,

                           [tex]c= \frac{Q}{cT}[/tex]

                           [tex]c = \frac{7000}{5000x25}[/tex]

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