Answer:
B) 300 J Kg^-1C^-1
Explanation:
By the formula of specific heat,
Q=mcT
where Q is heat energy
m is mass
c is heat capacity
T is change in temperature
By the given data,
Q = 15 KJ = 15 x 1000 = 15000J
m = 5 kg
T = 30°C - 20°C = 10°C
Now,
c=[tex]\frac{Q}{cT}[/tex]
c = [tex]\frac{15000}{5x10}[/tex]
c = 300 J Kg^-1C°^-1
