Question

This DNA strand consists of eight pairs of nitrogenous bases. How many different sequences of eight bases can you make? Explain how you found your answer.

Answer 1

Answer:

In the sequence of 8, it would be 4 (possible bases) to the power of 8 because you need to multiply 4, eight times for the number of sequences. Therefore, the answer is 65, 536 possible sequences.

Answer 2

There are 65,536 different possible sequences in a DNA strand consisting of eight pairs of nitrogenous bases.

• We have a DNA strand consisting of eight pairs of nitrogenous bases and we want to know how many different sequences of eight bases can we make, that is, how many combinations are possible.

• In DNA, there are 4 kinds of nitrogenous bases: Adenine (A), Guanine (G), Thymine (T) and Cytosine (C).

• Each position (P) can be occupied by any of the 4 bases (B).

• Since there are 8 positions, and the bases can be repeated, we can calculate the total number of different sequences (N) using the following expression.

$N = B^{P} = 4^{8} = 65,536$

There are 65,536 different possible sequences in a DNA strand consisting of eight pairs of nitrogenous bases.

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