Question

Hii om gosh so I am having a rough time trying to solve this problem for geometry. If you can tell me if what I have so far is right and what else I need, I’d really really appreciate it!!!

“3. Solve for x. Do not forget the statements and reasons.”

Answer 1

Answer:

x = 6

Step-by-step explanation:

In order to find the value of x, first we need to prove the triangles PQS and RQS as congruent. Let us do it.

$In\: \triangle PQS \:\& \:\triangle RQS\\\\

PS \cong SR.... (given) \\\\

\angle PSQ \cong\angle RQS... (\because QS\perp PR) \\\\

QS \cong QS... (Common \: side) \\\\

\therefore \triangle PQS \cong \triangle RQS.. (SAS \: Postulate) \\\\

\therefore PQ = QR... (BY\:CSCT) \\\\

\therefore 2x + 15 = 5x - 3\\\\

\therefore 2x - 5x = - 3 - 15\\\\

\therefore - 3x = - 18\\\\

\therefore x =\frac{-18}{-3}\\\\

\huge \red {\boxed {\therefore x = 6}}$

Answer 2

x=6

Both sides need to equal out to the same number

2•6 = 12
12+15= 27

5•6= 30
30-3= 27

Both sides equal out to the same number so 6 would be the correct answer.


Sorry I’m not very good at explaining things I hope this helps!!