Respuesta :
Answer:
this is tricky b/c of Sin() , Cos() and Tan() functions remember the Mnemonic SOH CAH TOA to help remember how those functions work
Step-by-step explanation:
so they asked for a function d(q) or d= q okay?
so what is that relationship of d & q since I wrote down the SOH CAH TOA reminder which of those might help us for this Sin()= Opp/ Hyp or Cos()=Adj/Hpy or Tan()=Opp / Adj So Molly will be standing where we are going to find the angle q, so from there, that point... the Adj side is d .. huh.. and the Opposite side is going to be the 630 foot tall Arch of that imaginary triangle from Molly to the base of the Arch and from Molly to the top of the Arch.. soooo lets use Tan() since that one seems to have the parts of info that we are given in this question.
Tan()=Opp / Adj where Tan(Ф) is q and that opposite side is the 630 minus Molly's 5'-3"height and d is the adjacent side so the formula now looks like this
q = (630- 5'3") / d if we then move those around and say that
d = (630-5'3") / q then we've got the equation in a pretty easy to see form.
We can also put in Tan() if we want so that the formula can be solved once you know the angle Molly is looking up at. so then the formula looks like d= (630-5'3")/ Tan(Ф)
if that makes sense? :)
The function for q in terms of d has d as the input variable and q as the
output.
Response:
- A function for q in terms of d is; [tex]\underline{q = arctan \left(\dfrac{624.75}{d} \right)}[/tex]
Method used to find the function for q
Height of St. Louis Arch = 630 feet
Angle of elevation = q
The distance from the base (of St. Louis Arch) = d
Height of Molly's eyes above the ground = 5 feet 3 inches
Required:
The function for q in terms of d
Solution:
3 inches = 0.25 feet
5 feet 3 inches = 5.25 feet
[tex]tan(q) = \dfrac{630 - 5.25}{d} = \mathbf{ \dfrac{624.75.}{d}}[/tex]
[tex]\underline{q = arctan\left(\dfrac{624.75}{d} \right)}[/tex]
Learn more about functions here:
https://brainly.com/question/18590720
