Question

Tris has two times as many quarters as dimes and three more nickels than dimes. If he has a total of $3.40, how many of each coin does he have?

Answer 1

Answer:

Janet has 12 dimes, 4nickels, and 8 quarters.

Step-by-step explanation:

Let N be the number of nickels

So she has 3N dimes =6N nickels and 2N quarters. So 2N q= 2x5=10N nickels. (1quarter=25 c and 1 nickel=5 cents, so 1 q=5 n)

So in all she has 6N+N+10N=17 N nickels

$3.40= 340 cents. = 17xNx5 cents. So N =4.