Question

An electric bulb is labeled 240v, 60w. How much current is taken by the bulb?​

Answer 1

Current = 0.25 A

Further explanation

Electric power i: electrical energy per unit time  

$\tt P=\dfrac{W}{t}$  

P = watt  

W = electrical energy, J  

t = time, s  

or

P = V.I  

V=voltages, volt

I=current,A

An electric bulb is labeled 240v, 60w,

So,

P = 60 watt

V=240 volt

$\tt I=\dfrac{P}{V}\\\\I=\dfrac{60}{240}=0.25~A$

Answer 2

Solution :

Power of that electric bulb is 60W.

Voltage of that bulb is 240V and we have to calculate the current (I).

• P = 60W
• V = 240V
• I = ?

Now, as we know that electrical power (P) is calculated by the formula :

• P = VI

Here,

• P is power
• V is voltage
• I is current

Substituting the values in the formula,

$\implies \: \sf{60 = (240)(I)}$

$\implies \: \sf{60 = (240) \times (I)}$

$\implies \: \sf{I \: = \: \dfrac{60}{240} }$

$\implies \: \sf{I \: = \: \cancel\dfrac{60}{240} }$

$\implies \: \sf{I \: = \: \dfrac{6}{24} }$

$\implies \: \sf{I \: = \: \cancel\dfrac{6}{24} }$

$\implies \: \sf{I \: = \: \dfrac{3}{12} }$

$\implies \: \sf{I \: = \: \cancel\dfrac{3}{12} }$

$\implies \: \sf{I \: = \: \dfrac{1}{4} }$

$\implies \: \sf{I \: = \: \cancel\dfrac{1}{4} }$

$\implies \: \red{\bf{I \: = \:0.4A}}$