Question

find the first four terms of the sequence:

an= 54+ 3(n-1) n= 1, 2, 3...

Answer 1

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 $\bold{Solution~Steps:}$

$1.)~54+3(1-1):$

• $\bold{Subtract~1~from~1~to~get~0.}$

• $\bold{Multiply~3~and~0~to~get~0.}$

• $\bold{Add~54~and~0~to~get~54.}$

$2.)~54+3(2-1):$

• $\bold{Subtract~1~from~2~to~get~1.}$

• $\bold{Multiply~3~and~1~to~get~3.}$

• $\bold{Add~54~and~3~to~get~57.}$

$3.)~54+3(3-1):$

• $\bold{Subtract~1~from~3~to~get~2.}$

• $\bold{Multiply~3~and~2~to~get~6.}$

• $\bold{Add~54~and~6~to~get~60.}$

$4.)~54+3(4-1):$

• $\bold{Subtract~1~from~4~to~get~3.}$

• $\bold{Multiply~3~and~3~to~get~9.}$

• $\bold{Add~54~and~9~to~get~63.}$

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 $\bold{Answers:}$

• $\bold{Term~1=\boxed{54}}$

• $\bold{Term~2=\boxed{57}}$

• $\bold{Term~3=\boxed{60}}$

• $\bold{Term~4=\boxed{63}}$

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