Question

Can anyone please help me with number 2 ❤️

Answer 1

Answer:

$A = 101.5825591635$°

Step-by-step explanation:

We can use the law of cosines.  We have a triangle with side lengths as attached. (See image.)

So we want to solve for angle A.

We do this by using:

$cos(A)=(b^2 + c^2 - a^2) / (2bc)$

Here we have:

a = 36

b = 27

c = 19

So we plug in to get:

$cos(A)=(27^2 +19^2-36^2)/(2*27*19)$

$cos(A)=-0.20077972709$

$A = 101.5825591635$°