Answer:
Let's define x = 0min when the tramway left the station.
We know that the height of the station is 4692 ft.
Then we can define this point as (0min , 4692ft).
And 4 minutes after, the elevation will be 5632ft, then we also have the point
(4min, 5632ft)
Now we can write the height as a function of time with a linear equation:
A linear relationship can be written as:
y = a*x + b
where a is the slope and b is the y-axis intercept.
For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:
a = (y2 - y1)/(x2 - x1).
In this case, the slope will be:
a = (5632ft - 4692ft)/(4min - 0min) = 235ft/min
And we already know the value of the y-intercept, this is the value that takes y when x = 0, this is 4692ft.
Then the equation is:
y = (235ft/min)*x + 4692ft
Where:
y = height
x = time in minutes.