Question

134d) Graph the hyperbola, identify the center, vertices, foci, and equations of the asymptotes

49y^2−25x^2−196y−200x−1429=0

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Answer 1

Answer:

Step-by-step explanation:

49y^2 - 25x^2 - 196y - 200x = 1429

49y^2-196y+196 - 25x^2-200x-400 = 1429+196-400

49(y-2)^2 - 25(x+4)^2 = 1225

(y-2)^2/25 - (x-4)^2/49 = 1

So now you know that you have an hyperbola with

center at (-4,2)

foci at (-4,2±$\sqrt{74}$)

vertices at (-4,2±5)

asymptotes 7y±20 = ∓5x+14