Answer:
10.3 m/s
Explanation:
Given that Bert is standing on a ladder picking apples in his grandfather’s orchard. As he pulls each apple off the tree, he tosses it into a basket that sits on the ground 5.0 m below at a horizontal displacement of 2.0 m from Bert.
Let us use pythagorean theorem
H = sqrt ( 5^2 + 2^2 )
H = sqrt ( 25 + 4 )
H = sqrt ( 29 )
H = 5.385 m
Using the third equation of motion
V^2 = U^2 + 2gH
But U = 0
V^2 = 2 × 9.8 × 5.385
V^2 = 105.549
V = sqrt ( 105.549 )
V = 10.27 m/s
Therefore, Bert will throw the apples (horizontally) in order to land in the basket as fast as 10.3 m/s approximately.