Question

Which equation shows y=3x−1/5 in standard form?

15x−5y=1
5x−15y=1
5x−15y=−1
15x+5y=−1
please only answer if you are 100% sure that its correct
ill give you branliest

Answer 1

Answer:

15x-5y=1

Step-by-step explanation:

y=3x−15

The standard form of a linear equation is Ax+By=C.

Multiply both sides by 5.

5y=5(3x−15)

Simplify 5(3x−15).

5y=15x−1

Rewrite the equation with the sides flipped.

15x−1=5y

Move all terms containing variables to the left side of the equation.

15x−5y−1=0

Add 1 to both sides of the equation.

15x−5y=1

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Answer 2

The equation that shows y=3x−1/5 in standard form is:

15x - 5y  =  1

The given equation is:

$y = 3x -\frac{1}{5}$

The given equation is of the form y = mx + b which is called the slope-intercept form of the line equation

where m represents the slope

and c represents the y-intercept

The standard form of the equation of a line is:

Ax  +  By  =  C

Multiply the equation $y = 3x -\frac{1}{5}$ through by 5

5y  =  5(3x)  -  5(1/5)

5y  =  15x  -  1

By rearranging the equation above, the resulting equation becomes:

15x - 5y  =  1

Therefore, the equation that shows y=3x−1/5 in standard form is:

15x - 5y  =  1

Learn more here: https://brainly.com/question/11380893