Answer:
a. 2.45 s b. 30.6 m
Explanation:
a. How long will it take for the ball to reach its highest point?
Using v = u - gt, we find the time it takes the ball to reach the highest point where v = velocity of ball at highest point = 0 m/s (since it momentarily stops), u = initial vertical velocity ball = 24.0 m/s (since it was hit straight up), g = acceleration due to gravity = 9.8 m/s² and t = time taken to reach highest point.
v = u - gt
t = (u - v)/g
t = (24.0 m/s - 0)/9.8 m/s²
t = 24.0 m/s ÷ 9.8 m/s²
t = 2.45 s
b. How high will the baseball travel?
Using y - y₀ = ut - 1/2gt² where y = maximum height of baseball, y₀ = height of bat above the ground where the ball was hit = 1.2 m, u = initial vertical velocity of ball = 24.0 m/s, g = acceleration due to gravity = 9.8 m/s² and t = time taken to reach highest point = 2.45 s
Substituting these values into the equation, we have
y - y₀ = ut - 1/2gt²
y - 1.2 m = 24.0 m/s × 2.45 s - 1/2 × 9.8 m/s² × (2.45 s)²
y - 1.2 = 58.8 - 29.41
y - 1.2 = 29.39
y = 29.39 + 1.2
y = 30.59 m
y ≅ 30.6 m
