Use Triangle ABC to find the trigonometric ratio.
tan B =

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[tex] \tan(B) = \frac{ \sin(B) }{ \cos(B) } = \frac{ \frac{8}{17} }{ \frac{15}{17} } = \frac{8}{15} \\ [/tex]
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The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. The value of Tan(B) will be equal to 8/15.
The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,
[tex]\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}[/tex]
where,
θ is the angle,
Perpendicular is the side of the triangle opposite to the angle θ,
The base is the adjacent smaller side of the angle θ.
The value of Tan(B) will be the ratio of the sides AC and BC. Therefore, the value of Tan(B) can be written as,
Tan(B) = AC / BC
Tan(B) = 8/15
Hence, the value of Tan(B) will be equal to 8/15.
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