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Consider the chemical reaction.

3MgCl2(aq)+2Na3PO4(aq)⟶Mg3(PO4)2(s)+6NaCl(aq)

Write the net ionic equation for the chemical reaction, including phases.

Respuesta :

Neetoo

Answer:

Net ionic equation:

3Mg²⁺(aq)  + 2PO₄³⁻(aq)     →    Mg₃(PO₄)₂(s)

Explanation:

Chemical equation:

3MgCl₂(aq) + 2Na₃PO₄(aq)    →    Mg₃(PO₄)₂(s) + 6NaCl(aq)

Ionic equation:

3Mg²⁺(aq)  + 6Cl⁻(aq)  + 6Na⁺(aq) + 2PO₄³⁻(aq)     →    Mg₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)

Net ionic equation:

3Mg²⁺(aq)  + 2PO₄³⁻(aq)     →    Mg₃(PO₄)₂(s)

The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The  Mg₃(PO₄)₂ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

Answer:

Net Ionic Equation in image attached

The spectator ions are Cl- and Na+

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