Respuesta :
Answer:
80g of A and 40g of B must be mixed.
Step-by-step explanation:
The mixes are:
Mix Protein (%) Carbohydrate (%)
Mix A 30 6
Mix B 20 2
The following equations can be formed using the provided data:
0.30A + 0.20B = 32...(i)
0.06A + 0.02B = 5.6...(ii)
Multiply (ii) by 5 and subtract the resultant equation from (i):
0.30A + 0.20B = 32
-0.30A - 0.10B = -28
0.10B = 4
B = 40
Substitute B in (i) and solve for A as follows:
0.30A + (0.20 × 40) = 32
0.30A = 32 - 8
0.30A = 24
A = 80
Thus, 80g of A and 40g of B must be mixed.
Using a system of equations, the number of grams of each mix required to make the right diet would be ; Mix A and B are 80 and 40 grams respectively.
For protein :
0.3a + 0.2b = 32 ------------(1)
0.06a + 0.02b = 5.6 - - - (2)
Multiply (1) by 1 and (2) by (5)
0.3a + 0.2b = 32 --------(3)
0.3a + 0.1b = 28 - - - - - (4)
Subtract (4) from (3)
0.1b = 4
b = 40
From (1) :
0.30a + (0.20)40 = 32
0.30a = 32 - 8
0.30a = 24
a = 80
Hence, the required grams of Mix A and B are 80 and 40 grams respectively.
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