Question

Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find all solutions whenever they exist.

Answer 1

Complete Question

Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find all solutions whenever they exist.

          $x - 3y = -10 \ \ \ and \ \ \ 4x +3y = 20$

Answer:

This system of linear equations has one solution which is  (x, y) = (2,4 )

Step-by-step explanation:

The first step is to add that two linear equations

             $x - 3y = -10\cdots (i) \\ 4x + 3y = 20\cdots (ii)\\------\\ 5x \ \ \ \ \ \ \ = 10$

=>        $x = 2$

substituting this into equation i  we have

      $2 - 3y = -10$

=>   $y = 4$

Hence this  system of linear equations has one solution which is  (x, y) = (2,4 )