Question

Calculate the mass defect for 239U239U, which has a mass of 239.05429 amuamu . (The mass of 11H11H is 1.00783 amuamu, and the mass of a neutron is 1.00866 amuamu .)

Answer 1

Answer:

The mass defect for U-239 is 1.93909 amu.

Explanation:

The mass defect can be calculated using the following equation:

$\Delta m = (Zm_{p} + Nm_{n}) - M$

Where:

$m_{p}$: is the proton mass = 1.00783 amu

$m_{n}$: is the neutron mass = 1.00866 amu        

M: is the mass of U-239 = 239.05429 amu

Z: is the number of protons = 92

N: is the number of neutrons = A - Z

A: is the atomic mass number = 239

$\Delta m = (Zm_{p} + Nm_{n}) - M = [92*1.00783 amu + (239 - 92)*1.00866 amu] - 239.05429 amu = 1.93909 amu$

Therefore, the mass defect for U-239 is 1.93909 amu.

I hope it helps you!