Question

What is an equation of the line that passes through the points (6,1) and (-6,-1)

Answer 1

Answer:

x - x1/ x2- x1 = y -y1 / y2-y1

x - 6/ -6-6= y - 1/ -1 -1

x -6/-12 = y -1 /-2

-2(x-6) = -12 (y-1)

-2x +12 = -12y +12

12y = 2x +12-12

y= 2x/12

y= x/6

Answer 2

y=1/6x
The equation of a line can be written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Using the above formula,

Substitute the value of m into the equation:

To find the value of c, substitute a pair of coordinates.
When x=6, y=1,
1=1/6(6)+c
1=1+c
c=1-1
c=0
y=1/6x