Answer:
Explanation:
2K₂Cr₂O₇ + 8H₂SO₄ + 3CH₃OH= 2 K₂SO₄ + 2Cr₂( SO₄)₃ + 3 HCOOH + 11 H₂O .
1.9 g of CH₃OH = 1.9 / 32 moles of CH₃OH
moles of given CH₃OH = .059375 moles
3 moles of CH₃OH reacts with 2 moles of K₂Cr₂O₇
.059375 moles of CH₃OH reacts with 2x .059375 / 3 moles of K₂Cr₂O₇
Moles of K₂Cr₂O₇ required = 2x .059375 / 3 = .039583 moles
Let V be the volume in litre required
V x .00143 = .039583
V = 27.68 L
