Question

A full-wave bridge-rectifier circuit with a 1-k load operates from a 120-V (rms) 60-Hz household supply through a 12-to-1 step-down transformer having a single secondary winding. It uses four diodes, each of which can be modeled to have a 0.7-V drop for any current. What is the peak value of the rectified voltage across the load

Answer 1

Answer:

peak value of the rectified voltage across the load is 12.7667 V

Explanation:

given data

load operates = 1 K

solution

we ger here peak value of the rectified voltage across the load that is express as

Vo = V (secondary )  - 2 Vd   ....................1

we get here input voltage of transfer that is

V (primary) = √2 × vrms   ..................2

V (primary) = √2 × 120

V (primary) = 169.70   =   170 V

and

V (secondary ) = V (primary) × $\frac{1}{12}$       ................3

V (secondary ) = 170× $\frac{1}{12}$     = 14.167 V

so

put value in eq 1 we get

Vo = 14.167  - 2 (0.7)

Vo = 12.7667 V