Answer:
For bond it is $16,000
And, for stocks it is $8,000
Step-by-step explanation:
Let us assume the Tran invested x amount in bonds and y amount in stocks
So, the profit could be
P = 0.06x + 0.08y
The total amount is $24,000
so, the equation would be
x + y = $24,000
Now in the case of atleast twice, the equation would be
x ≥ 2y
And, in the case of not be greather than $18,000, the equation would be
x ≤ $18,000
The linear programming problem would be shown below:
maximum P = 0.06x + 0.08y
subjected to
x + y = $24,000
x ≥ 2y
x ≤ $18,000
x ≥0, y ≥0
Now use the graphical method, the critical point is ($18,000,$6,000) or ($6,000, $18,000)
In the case when we have to maximise the profits
For bond it is $16,000
And, for stocks it is $8,000
The maximize profit for is bond is $18000.
The maximize profit for stocks is $6000
Suppose that ; Mr. Tran invested x amount in bonds and y amount in stocks.
According to given question;
The bonds earn 6% and stocks earn 8% profit ,
Then profit could be ,
P = 0.06 + 0.08
Total amount = $24,000
So, the equation can be return as
x + y = $24000
The money invested in bonds at least twice the equation can be return as[tex]x\geq 2y[/tex]
the money invested in the bonds not greater than will be
[tex]x\leq $18000[/tex]
The linear programming would be shown below
By the graphical method maximize the profit .
The critical points shown in the attached image is ($6000,$18000) & ($16000,$18000)
Thus the maximize profit for bond is $18000
The maximize profit for stocks is $6000.
For more details follow the link given below
https://brainly.in/question/41954776
