Question

6-36. Calculate [H ] and pH for the following solutions: (a) 0.010 M HNO 3 (b) 0.035 M KOH (e) (c) 0.030 MHCl

Answer 1

Answer:

a)2

b)12.5

c)1.5

Explanation:

a)

pH = -log [H^+]

pH = -log [0.01]

pH = 2

b)

pOH = -log[OH^-]

pOH = -log [0.035]

pOH= 1.5

But

pH + pOH = 14

pH = 14 - pOH

pH= 14 - 1.5

pH = 12.5

c)

pH = -log[H^+]

pH= -log[0.030]

pH = 1.5