Question

Task C has two immediate predecessors, Tasks A and B. Task C also has two immediate followers, Tasks D and E. Task A has an early finish time of 3 days, and Task B has an early finish time of 5 days. Task D has a late start time of 10 days and Task E has a late start time of 8 days. Task C is 2 days long. What is the early finish time of Task C

Answer 1

Answer:

7 days

Explanation:

Calculation for the early finish time of Task C

First step is to find the Early Start of task C

Using this formula

Early Start of task C = MAX (Early Finish of task A, Early Finish of task B)

Let plug in the formula

Early Start of task C= MAX(3,5)

Early Start of task C = 5

Now let calculate the Early Finish time of Task C

Using this formula

Earliest Finish = Earliest Start + Activity Duration

Let plug in the formula

Earliest Finish of task C = 5 + 2

Earliest Finish of task C = 7 days

Therefore the early finish time of Task C will be 7 days

Answer 2

The early finish time of task C is the sum of the early start time and the activity duration of the task. Hence, the early finish time of task C is 7 days.

Given the Parameters :

• Activity time of task C = 2 days
• Early finish, Task A = 3 days
• Early finish, Task B = 5 days

The early finish time of task C :

Early start time possible + Activity time of task C

Maximum value of the finish time of the preceeding task :

Early start time of task C = maximum(3, 5)

Early start time of task C = 5 days

Early finish time of C = 5 days + Activity time

Early finish time of task C = 5 days + 2 days = 7 days

Therefore, the early finish time of task C is 7 days

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