Question

Ignoring the CuSO4, and based solely on the volume and molarity of the Na2S(aq), how many grams of CuS(s) would be produced by this

Answer 1

Answer:

 0.019122 grams of CuS(s) would be produced .

Explanation:

Given , volume of $CuSO_{4}$ is 4ml = 0.004 L

            volume of $Na_{2}S$ is 2ml = 0.002 L

$CuSO_{4} + Na_{2}S \rightarrow Na_{2}SO_{4} + CuS$

Moles of $CuSO_{4}$ = Molarity x volume (L)

                          = 0.1M x 0.004 L

                              = 0.0004 moles

Moles of $Na_{2}S$ = 0.1M  x 0.002 L

                            = 0.0002 moles

1 mole of $Na_{2}S \rightarrow$ 1 mole of $CuS$

Therefore , 0.0002 moles $Na_{2}S \rightarrow$ 1mole of $CuS$

Mass of $CuS$ =  Moles x molar mass

                     = 0.0002 x  95.611

                  = 0.019122 grams .

Hence the answer is 0.019122 grams.