Consider a surface at a uniform temperature of 1000 K. Determine the maximum rate of thermal radiation that can be emitted by this surface, in W/m2.

Respuesta :

Answer:

The value is [tex]E_b_{max} = 56.700 *10^{3} \ W/m^2[/tex]

Explanation:

From the question we are told that

   The uniform temperature is  [tex]T = 1000 \ K[/tex]

Gnerally the rate of thermal radiation is mathematically represented as

         [tex]E_b = \epsilon * \sigma* T^4[/tex]

Generally  [tex]\epsilon[/tex]  is the emissivity and at maximum the value is  1

                [tex]\sigma[/tex]  is the Stefan Boltzmann constant with value  [tex]\sigma = 5.67 *10^{-8} \ W/m^2 \cdot K^4[/tex]

So

     [tex]E_b_{max} = 1 * 5.67 *10^{-8}* 1000^4[/tex]

=>   [tex]E_b_{max} = 56.700 *10^{3} \ W/m^2[/tex]

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