Which equation represents the line with slope 1/4 that passes through (–4, 8)?

Answer:
[tex]y = \frac{1}{4}x +9[/tex]
Step-by-step explanation:
Given
[tex](x,y) = (-4,8)[/tex]
[tex]m = \frac{1}{4}[/tex] --- slope
Required
Determine the line equation
This can be solved using:
[tex]y - y_1 = m(x - x_1)[/tex]
Substitute values for m, x1 and yi.
[tex]y - 8 = \frac{1}{4}(x - (-4))[/tex]
[tex]y - 8 = \frac{1}{4}(x +4)[/tex]
[tex]y - 8 = \frac{1}{4}x +1[/tex]
Add 8 to both sides
[tex]y - 8+8 = \frac{1}{4}x +1+8[/tex]
[tex]y = \frac{1}{4}x +9[/tex]
We want to see which equation represents the line with the desired characteristics.
The correct option is B: y = (1/4)*x + 9
We know that a general line is written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
Here we do know that our line must have a slope 1/4, replacing that in the general equation we get:
y = (1/4)*x + b
We also know that our line passes through (-4, 8).
This means that y = 8 when x = -4, replacing that in the equation we get:
8 = (1/4)*-4 + b
8 = -1 + b
8 + 1 =b = 9
Then the equation is:
y = (1/4)*x + 9
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