Answer:
x = 2[tex]\sqrt{5}[/tex]
Step-by-step explanation:
The radius of the circle = 4 + 2 = 6
Thus the radius is from the centre to the top of segment x
Using Pythagoras' identity in the right triangle formed, that is
x² + 4² = 6²
x² + 16 = 36 ( subtract 16 from both sides )
x² = 20 ( take square root of both sides )
x = [tex]\sqrt{20}[/tex] = 2[tex]\sqrt{5}[/tex]
