sameralsakka sameralsakka
  • 26-10-2020
  • Mathematics
contestada

How do I solve this?
50e^(0.035x)=200

Respuesta :

jimrgrant1 jimrgrant1
  • 26-10-2020

Answer:

x ≈ 39.608

Step-by-step explanation:

Using the rule of logarithms

log[tex]x^{n}[/tex] = nlogx and lne = 1

Given

50[tex]e^{0.035x}[/tex] = 200 ( divide both sides by 50 )

[tex]e^{0.035x}[/tex] = 4 ( take the ln of both sides )

ln[tex]e^{0.035x}[/tex] = ln4 , that is

0.035xlne = ln4

0.035x = ln4 ( divide both sides by 0.035 )

x = [tex]\frac{ln4}{0.035}[/tex] ≈ 39.608 ( to 3 dec. places )

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