Question

If the distance of an object is determined from the relation: d = a X + b Y Where: (d) is the distance covered by the body. (a) is a physical quantity which has a dimensions (L T^-1). (b) Is a physical quantity which has a dimensions (L T^-2). So: *

The dimension formula of (X) is T and that of (Y) is T^2.

The dimension formula of (X) is T and that of (Y) is T^-2

The dimension formula of (X) is T^-1 and that of (Y) is T^2.

The dimension formula of (X) is T^-1 and that of (Y) is T^-2.​

Answer 1

Answer:

The dimension formula of X is T and that of Y is  T^2

Explanation:

                     d = aX + bY is ACTAULLY  $S = V_{i} t + \frac{1}{2} a t^{2}$

                     so v = LT^-1

                          t = T

                          numerics do not have any dimensional formula so ignore $\frac{1}{2}$

                          a = LT^-2

                          t = T^2

                         So answer for x is T and y T^2