A local farm has a 0.75 acre field that was planted with 26,100 corn plants. one acre is equivalent to 43,500 square feet.
Assuming the same planting density, how many corn plants could they plant on a field with an area of 80,000 square feet?
The options are:
A. 34,800
B. 48,000
C. 60,000
D. 64,000
E. 100,000
(Please answer this as fast as possible)

So first what you want to do is find how many acres you're working with. Since you know that one acre is 43,500 square feet, you can find the number of acres you're working with by dividing 80,000 theoretical square feet by your given conversion:

80,000/43,500 is 1.83908045977

After this what you want to do is divide the theoretical acres by the conversion that was given to you in the problem:

1.83908045977/.075 is 2.45210727969

Now that you have this number, you would multiply the number of corn plants that you have in order to get the theoretical number of plants that you could plant on an area of that theoretical size of 80,000 square feet:

2.45210727969 times 26,100 is 64,000 even.

batolisis batolisis · Answer 2 · 2022-05-17T11:37:55+02:00

The number of corn plants that could be planted on 80,000 square feet is : 64000.

What is an acre?

An acre is a unit for expressing the area of big shapes and objects like fields, farm lands.

Analysis:

If 1 acre is equivalent to 43500square feet, then 0.75 acre would be

0.75 x 43500 = 32625 square feet.

If 325625 square feet produce 26,100 corn plants , then 80,000 square feet would produce : [tex]\frac{80000 x 26100}{32625}[/tex] = 64000 corn plants.

Learn more about area : brainly.com/question/25292087

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