Question

What amount of hydrogen gas would be necessary to to produce 14.0 mol NH3(g)(assuming there is enough nitrogen gas to complete the reaction)?

Answer 1

Answer:

Amount of hydrogen gas needed 42 g.

Explanation:

Given data:

Amount of ammonia produced = 14.0 mol

Amount of hydrogen gas needed = ?

Amount of nitrogen = excess

Solution:

Chemical equation:

N₂ + 3H₂      →    2NH₃

Now we will compare the moles of hydrogen with ammonia.

            NH₃              :             H₂

              2                :               3

             14.0            :            3/2×14.0 = 21 mol

Mass of hydrogen needed:

Mass = number of moles × molar mass

Mass = 21 mol × 2 g/mol

Mass = 42 g