Answer:
The population mean and standard deviation of the uniform distribution of random numbers are 4.5 and 2.60 respectively.
Step-by-step explanation:
The mean and standard deviation of a Uniform distribution is:
[tex]\mu=\frac{a+b}{2}\\\\\sigma=\sqrt{\frac{(b-a)^{2}}{12}}[/tex]
Here the value of a and b are:
a = 0
b = 9
Compute the population mean and standard deviation of the uniform distribution of random numbers as follows:
[tex]\mu=\frac{a+b}{2}=\frac{0+9}{2}=4.5\\\\\sigma=\sqrt{\frac{(b-a)^{2}}{12}}=\sqrt{\frac{(9-0)^{2}}{12}}=2.60[/tex]
Thus, the population mean and standard deviation of the uniform distribution of random numbers are 4.5 and 2.60 respectively.