Question

The larger of two numbers is 11 more than twice the smaller number. The sum of the numbers is 1 less than seven times the smaller number. Find the numbers

Answer 1

X
The large of two numbers is/= 11 more (+11) than twice the smaller number (2y)
X= 2y+11

The sum of the numbers (x+y) is/= to 1 less than (-1) seven times (7y)
X+y=7y-1

Substitute X= 2y+11 into X+y=7y-1


2y+11 +y=7y-1
Simplify

3y+11=7y-1
12=4y
Y=3

Put y into the first equation

X= 2y+11
X =2*3+11
X=6+11
X=17

Answer 2

Answer:

bigger: 16, smaller: 2 2/5

Step-by-step explanation:

x = smaller number

11 + 2x + x = 7x - 1

+1                     +1

12 + 2x = 7x

    -2x     -2x

12 = 5x, x = 2 2/5 = smaller number

11 + 5 = 16 = bigger number