Answer:
5.3m/[tex]s^{2}[/tex]; 7.45m/[tex]s^{2}[/tex]
Explanation:
the magnitude of a=(change in speed)/(the time took to accelerate to the speed above)
So for that sports car, a=(26.8m/s-0m/s)/(5.1s)=5.2549m/[tex]s^{2}[/tex], knowing from the question that the sig fig of this question depend on "5.1 seconds", so the answer should be 5.3 m/[tex]s^{2}[/tex]
For the rocket, a=(447m/s-0m/s)/(1 minute)=(447m/s)/(60s)=7.45m/[tex]s^{2}[/tex]