Solve: Sin(11 pi/2 + x) = -1/2 for [Pi, 2Pi].
StartFraction 4 pi Over 3 EndFraction
StartFraction 5 pi Over 3 EndFraction
StartFraction 7 pi Over 6 EndFraction
StartFraction 11 pi Over 6 EndFraction

Solve Sin11 pi2 x 12 for Pi 2Pi StartFraction 4 pi Over 3 EndFraction StartFraction 5 pi Over 3 EndFraction StartFraction 7 pi Over 6 EndFraction StartFraction class=

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Answer: B

The answer above is correct. It would be 5pi/3.

Step-by-step explanation: Edge2021

I just got it right on my quiz.

The value of the x is equal to the 5pi/3.

The expression is

[tex]\sin \left(11\cdot \frac{\pi }{2}+x\right)=-\frac{1}{2},\:\pi \le \:x\le \:2\pi[/tex]

The value of the given expression.

What is the expression?

An expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

We have,

[tex]\sin \left(11\cdot \frac{\pi }{2}+x\right)=-\frac{1}{2},\:\pi \le \:x\le \:2\pi[/tex]

[tex]11\cdot \frac{\pi }{2}+x=\frac{7\pi }{6}+2\pi n,\:11\cdot \frac{\pi }{2}+x=\frac{11\pi }{6}+2\pi n[/tex]

[tex]x=2\pi n-\frac{13\pi }{3},\:x=2\pi n-\frac{11\pi }{3}[/tex]

[tex]x=\frac{5\pi }{3}[/tex]

Therefore, The value of the x is equal to the 5pi/3.

To learn more about the sin function visit:

https://brainly.com/question/16818112

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