JimmyFinestein
JimmyFinestein JimmyFinestein
  • 28-09-2016
  • Mathematics
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X = -8 ± √(8)^2 - 4(1)(12)
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2(1)

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nobillionaireNobley
nobillionaireNobley nobillionaireNobley
  • 28-09-2016
[tex]x=\frac{-8\pm\sqrt{8^2-4(1)(12)}}{2(1)}\\x=\frac{-8\pm\sqrt{64-48}}{2}\\x=\frac{-8\pm\sqrt{16}}{2}\\x=\frac{-8\pm\sqrt{16}}{2}\\x =\frac{-8\pm4}{2}\\x=\frac{-8+4}{2} \ or \ \frac{-8-4}{2}\\x=\frac{-4}{2} \ or \ \frac{-12}{2}\\x=-2 \ or \ x=-6[/tex]
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