Respuesta :
6x^2 + 37x - 60 = 6x^2 - 8x + 45x - 60 = 2x(3x - 4) + 15(3x - 4) = (3x - 4)(2x + 15)
For this case we have the following polynomial:
[tex] 6x ^ 2 + 37x - 60
[/tex]
Rewriting the polynomial in the term of degree 1 we have:
[tex] 6x ^ 2 + 37x - 60 = 6x ^ 2 - 8x + 45x - 60
[/tex]
Then, we group the expression obtained as:
[tex] (6x ^ 2 - 8x) + (45x - 60)
[/tex]
In the first parenthesis we do 2x common factor.
In the second parenthesis we make a common factor 15.
We have then:
[tex] 2x (3x - 4) + 15 (3x - 4)
[/tex]
Then, we make a common factor of both parentheses:
[tex] (3x - 4) (2x + 15)
[/tex]
Answer:
The expressions that represent integer factors of [tex] 6x ^ 2 + 37x - 60 [/tex] for all values of x are:
[tex] (3x - 4) (2x + 15)
[/tex]
option 1