Question

The intercepts of the equation x^2 + 4y^2 = 16 are ___
PLEASE HELP

Answer 1

yintercepts are where x=0
set to zero to solve

0^2+4y^2=16
4y^2=16
divide 4
y^2=4
sqrt both sides
y=+/-2

xintercept is where y=0

x^2+4(0)^2=16
x^2+0=16
x^2=16
sdqrtboth sides
x=+/-4

yintercepts are (0,2) and (0,-2)
xintercepts are (4,0) and (-4,0)