calebburch calebburch

27-09-2016
Chemistry

contestada

How many moles of MgSiO3 are in 233 g of the compound?

Respuesta :

05-10-2016

m = 233g
M = 24 + 28+ 16 * 3 = 100g/mol

n = m/M = 233g / 100 g/mol = 2,33mol

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