Question

what do you call a female bug that floats

Answer 1

You call a female bug that floats a buoyant girl ant.

Answer 2

Answer:

Part 1) T

Part 2) L

Part 3) A

Part 4) Y

Part 5) T

Part 6) I

Part 7) U

Part 8) A

Part 9) N

Part 10) G

Part 11) B

Part 12) A

Part 13) N

Part 14) R

Part 15) O

The final answer is

A buoyant girl ant

Step-by-step explanation:

see the attached figure to better understand the problem

Part 1) we have

$2x\geq-6$ ----> inequality A

Divide by $2$ both sides

$x\geq-3$ ------> the solution inequality A is the interval [-3,∞)

$x-1 < 0$ -----> inequality B

Adds $1$ both sides

$x < 1$  ------> the solution inequality B is the interval (-∞,1)

The solution of the system of inequalities is the interval -----> [-3,1)

The solution is the letter T

Part 2) we have

$-7x<14$ ----> inequality A

Divide by $7$ both sides

$-x<2$ -----> multiply by $-1$

$x>-2$------> the solution inequality A is the interval (-2,∞)

$3x+2\leq 8$ -----> inequality B

Adds $-2$ both sides

$3x\leq 6$

Divide by $3$ both sides

$x\leq 2$  ------> the solution inequality B is the interval (-∞,2]

The solution of the system of inequalities is the interval -----> (-2,2]

The solution is the letter L      

Part 3) we have

$--8<x-5$ ----> inequality A

rewrite

$x-5>-8$

Adds $5$ both sides

$x>-3$ ------> the solution inequality A is the interval (-3,∞)

$x-5<-3$ -----> inequality B

Adds $5$ both sides

$x<2$ ------> the solution inequality B is the interval (-∞,2)

The solution of the system of inequalities is the interval -----> (-3,2)

The solution is the letter A  

Part 4) we have

$1\leq4x+1$ ----> inequality A

rewrite

$4x+1\geq 1$

Adds $-1$ both sides

$4x\geq 0$

Divide by $4$ both sides

$x\geq 0$ ------> the solution inequality A is the interval [0,∞)

$4x+1\leq 17$ -----> inequality B

Adds $-1$ both sides

$4x\leq 16$

Divide by $4$ both sides

$x\leq 4$  ------> the solution inequality B is the interval (-∞,4]

The solution of the system of inequalities is the interval -----> [0,4]

The solution is the letter Y          

Part 5) we have

$1\leq -2x+7$ ----> inequality A

rewrite

$-2x+7\geq 1$

Adds $-7$ both sides

$-2x\geq -6$

Divide by $2$ both sides

$-x\geq -3$ ------> multiply by $-1$

$x\leq 3$ ------> the solution inequality A is the interval (-∞,3]

$-2x+7<9$ -----> inequality B

Adds $-7$ both sides

$-2x<2$

Divide by $2$ both sides

$-x<1$ ------> multiply by $-1$

$x>-1$ ------> the solution inequality B is the interval (-1,∞)

The solution of the system of inequalities is the interval ----->(-1,3]

The solution is the letter T        

Part 6) we have

$3x-1<-7$ ----> inequality A

Adds $1$ both sides

$3x<-6$

Divide by $3$ both sides

$x<-2$ ------> the solution inequality A is the interval (-∞,-2)

$4x+9\geq 13$ -----> inequality B

Adds $-9$ both sides

$4x \geq 4$

Divide by $1$ both sides

$x \geq 1$ ------> the solution inequality B is the interval [1,∞)

The solution of the system of inequalities is the interval ----->(-∞,-2) U [1,∞)

The solution is the letter I            

Part 7) we have

$-5x>15$ ----> inequality A

Divide by $5$ both sides

$-x>3$

multiply by $-1$

$x<-3$ ------> the solution inequality A is the interval (-∞,-3)

$x-5>-6$ -----> inequality B

Adds $5$ both sides

$x>-1$ ------> the solution inequality B is the interval (-1,∞)

The solution of the system of inequalities is the interval ----->(-∞,-3) U (-1,∞)

The solution is the letter U  

Part 8) we have  

$4-15x\geq 4$ ----> inequality A  

Adds $-4$ both sides

$-15x\geq 0$

Divide by $15$ both sides

$-x\geq 0$ -----> multiply by $-1$

$x\leq 0$ ------> the solution inequality A is the interval (-∞,0]

$12x>36$ -----> inequality B

Divide by $12$ both sides

$x>3$ ------> the solution inequality B is the interval (3,∞)

The solution of the system of inequalities is the interval ----->(-∞,0] U (3,∞)

The solution is the letter A  

see the complete answer in the attached file