Respuesta :
The statement suppose that r varies directly with s and inversely with t is best represented as:
r α s/t
To make it into equality, we insert a proportionality constant, k:
r = ks/t
Using the initial conditions, we solve for k.
r = ks/t
r = 2 when s = 3 and t = 12
2 = k(3)/12
k = 8
Thus, when s = 5 and t = 4,
r = 8(5)/4
r = 10 -----> OPTION C
r α s/t
To make it into equality, we insert a proportionality constant, k:
r = ks/t
Using the initial conditions, we solve for k.
r = ks/t
r = 2 when s = 3 and t = 12
2 = k(3)/12
k = 8
Thus, when s = 5 and t = 4,
r = 8(5)/4
r = 10 -----> OPTION C
A correct option is an option (c)
Given values are,
[tex]r = 2[/tex] when [tex]s = 3 , t = 12[/tex]
According to the given question, the relation is,
[tex]r\propto \frac{s}{t}\\r=k\frac{s}{t}...(1)[/tex]
Substituting the values [tex]r = 2[/tex] when [tex]s = 3 , t = 12[/tex] into equation (1)
[tex]2=\frac{3k}{12} \\k=\frac{24}{3} \\k=8[/tex]
Since we have to find the value [tex]r[/tex] again from equation (1)
[tex]r=\frac{8\times5}{4} \\r=10[/tex]
So, the required value r is 10.
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