The Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4-2. When the conductivity is at a minimum, what must be true about the amount of Ba(OH)2 compared to H2SO4? Also, why does it not conduct at this low point?
The amount of the two reactants are the same when conductivity is low. There are no excess between the reactants. The precipitate BaSO4 is insoluble in the aqueous solution. Therefore, there are no ions which makes the conductivity at minimum.
