Question

1. You have three molecules of glucose (3C6H12O6). How many carbon atoms do you have?. . A. 3. . B. 6. . C. 18. . D. 36. 2. Which of the following is a homogenous mixture of two or more pure substances? . A. oxygen. B. water. C. air. D. alcohol.

Answer 1

One molecule of glucose has 6 carbon atoms. So if you have three molecules of glucose, simply multiply 3 by 6 carbon atoms. The correct answer is C. 18 Carbon atoms. 

The correct answer for the second questions is C. Air. A homogenous mixture is a mixture in which its components are uniformly distributed throughout the mixture. It has a sigle phase.

Answer 2

Answer:

1. C. 18 atoms of carbon

2. C. Air

Explanation:

1. The formula of one molecule of glucose is

$C_{6}H_{12}O_{6}$

In this formula we have:

Carbon: 6 atoms

Hydrogen: 12 atoms

Oxygen: 6 atoms

if we have three glucose molecules, we have to multiply the formula ($C_{6}H_{12}O_{6}$) by three

$3(C_{6}H_{12}O_{6})\\C_{18}H_{36}O_{18}$

In this formula we have:

Carbon: 18 atoms

Hydrogen: 36 atoms

Oxygen: 18 atoms

2. A homogeneous mixture is the combination of 2 or more unidentifiable elements or substances within the solution.

Homogeneous mixtures are characterized by being uniform, this means that the elements that compose it are not distinguishable.

A. Oxygen is molecule $O_{2}$

B. Water is molecule compose by 2 elements $H_{2}O$

C. Air is a mixture of several gases.

D. Alcohol is compound of carbon, hydrogen and oxygen.$C_{2}H{5}OH$