Question

The ages of three brothers are consecutive even integers. Three times the age of the youngest brother exceeds the oldest brother's age by 48 years. What is the age of the youngest brother?

Answer 1

Answer:

28 years

Step-by-step explanation:

youngest brother's age = x

middle brother's age = x+2

oldest brother's age = x+4

3(x-2) = (x+2)+48

[simplify]

3x-6 = x+50

[add 6 to each side]

3x = x+56

[subtract x from each side]

2x = 56

[divide each side by 2]

x = 28